2[x-(4x-3)]=0

Solution for 2[x-(4x-3)]=0 equation:

Simplifying
2[x + -1(4x + -3)] = 0

Reorder the terms:
2[x + -1(-3 + 4x)] = 0
2[x + (-3 * -1 + 4x * -1)] = 0
2[x + (3 + -4x)] = 0

Reorder the terms:
2[3 + x + -4x] = 0

Combine like terms: x + -4x = -3x
2[3 + -3x] = 0
[3 * 2 + -3x * 2] = 0
[6 + -6x] = 0

Solving
6 + -6x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -6x = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -6x = 0 + -6
-6x = 0 + -6

Combine like terms: 0 + -6 = -6
-6x = -6

Divide each side by '-6'.
x = 1

Simplifying
x = 1